Problem

Suppose the data to the right represent Male Female Child Total the survival data for the a certain ship that sank. The Survived 243 396 79 718 males are adult males and the Died 1,099 72 53 1,224 females are adult females. Complete parts (a) Total $\quad 1,342$ 468 132 1,942 through (j). C. No, because the survival rate for men was higher than the survival rates for women and children. (j) Suppose two females are randomly selected. What is the probability both survived? (Round to four decimal places as needed.)

Solution

Step 1 :Given that there are 468 females in total and 396 of them survived, the probability that one female survived is \(\frac{396}{468}\).

Step 2 :Since we are selecting two females, we need to calculate the probability that the second female also survived given that the first one did.

Step 3 :This is calculated as \(\frac{396-1}{468-1}\) because we have one less female and one less survivor after the first selection.

Step 4 :The total probability is the product of these two probabilities, which is approximately 0.7157.

Step 5 :Final Answer: The probability that both females selected survived is approximately \(\boxed{0.7157}\).

From Solvely APP
Source: https://solvelyapp.com/problems/18366/

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