Problem
The sine of \( 37^{\circ} \) is equal to the cosine of what angle? Enter your answer in the box.
Solution
Step 1 ：\( \sin{37^{\circ}} = \cos{(90^{\circ} - 37^{\circ})} \)
Step 2 ：\( 90^{\circ} - 37^{\circ} = 53^{\circ} \)
Step 3 ：\( \cos{53^{\circ}} \)
