Step 1 :The probability of getting a head in a single coin flip is \(\frac{1}{2}\).
Step 2 :Since the coin flips are independent events, the probability of getting seven heads in a row is \(\left(\frac{1}{2}\right)^7\).
Step 3 :To find out how many times this event would occur in ten thousand trials, we multiply the probability by the number of trials.
Step 4 :\(prob_{head} = 0.5\)
Step 5 :\(num_{flips} = 7\)
Step 6 :\(num_{trials} = 10000\)
Step 7 :\(prob_{sevenheads} = 0.0078125\)
Step 8 :\(expected_{occurrences} = 78.125\)
Step 9 :Round \(expected_{occurrences}\) to the nearest whole number, we get 78.
Step 10 :Final Answer: It is expected that the event would result in seven heads about \(\boxed{78}\) times.