Step 1 :The outcomes in F or G are the union of the sets F and G. So, F or G = \(\{3, 4, 5, 6, 7, 8, 9, 10\}\).
Step 2 :The probability of F or G by counting the outcomes is the number of outcomes in F or G divided by the total number of outcomes in the sample space. So, \(P(F \text{ or } G) = \frac{8}{12} = 0.667\).
Step 3 :The general addition rule for probability states that the probability of F or G is equal to the probability of F plus the probability of G minus the probability of both F and G. So, \(P(F \text{ or } G) = P(F) + P(G) - P(F \text{ and } G)\).
Step 4 :The probability of an event is the number of outcomes in the event divided by the total number of outcomes in the sample space. So, \(P(F) = \frac{5}{12} = 0.417\) and \(P(G) = \frac{4}{12} = 0.333\).
Step 5 :The probability of both F and G is the probability of the intersection of F and G, which is the number of outcomes in both F and G divided by the total number of outcomes in the sample space. So, \(P(F \text{ and } G) = \frac{1}{12} = 0.083\).
Step 6 :Substituting these values into the general addition rule gives \(P(F \text{ or } G) = 0.417 + 0.333 - 0.083 = 0.667\).
Step 7 :Final Answer: The outcomes in F or G are \(\boxed{\{3, 4, 5, 6, 7, 8, 9, 10\}}\). The probability of F or G by counting the outcomes is \(\boxed{0.667}\). The probability of F or G using the general addition rule is also \(\boxed{0.667}\).