Question 10 of 26 What is the distance between the points \( (4,10) \) and \( (-3,-14) \) on the coordinate plane? A. 10 units B. 50 units C. 25 units D. 5 units

Step 1 ：Determine the differences in \(x\) and \(y\) coordinates: \(\Delta x = -3 -4 = -7\), \(\Delta y = -14 - 10 = -24\)

Step 2 ：Calculate the square of differences: \(\Delta x^{2} = (-7)^{2} = 49\), \(\Delta y^{2} = (-24)^{2} = 576\)

Step 3 ：Apply the distance formula: \(d = \sqrt{(\Delta x^{2} + \Delta y^{2})} = \sqrt{49 + 576} = \sqrt{625} = 25\sqrt{2}\)