Evaluate the function at the given value of the variable. \[ f(x)=3 x^{2}+2 x-1 \] a. $f(5)$ b. $f(-6)$ a. $f(5)=$ b. $f(-6)=$

Step 1 ：Given the function \(f(x)=3 x^{2}+2 x-1\), we are asked to evaluate the function at \(x=5\) and \(x=-6\).

Step 2 ：Substitute \(x=5\) into the function: \(f(5)=3(5)^{2}+2(5)-1\).

Step 3 ：Simplify to get \(f(5)=75+10-1=84\).

Step 4 ：Substitute \(x=-6\) into the function: \(f(-6)=3(-6)^{2}+2(-6)-1\).

Step 5 ：Simplify to get \(f(-6)=108-12-1=95\).

Step 6 ：Final Answer: \(a. f(5)=\boxed{84}\) \(b. f(-6)=\boxed{95}\)