Step 1 :The first step to solve the inequality $4 x+6 \leq 3 x+11$ is to isolate the variable $x$ on one side of the inequality. To do this, we can subtract $3x$ from both sides of the inequality to get $x + 6 \leq 11$. Then, we can subtract $6$ from both sides of the inequality to get $x \leq 5$. This is the solution to the inequality.
Step 2 :To graph the solution, we need to draw a number line and mark the point $5$ on it. Since the inequality is less than or equal to, we need to include the point $5$ in the solution set. This means that we need to draw a closed circle at $5$. Then, since $x$ is less than or equal to $5$, we need to shade the number line to the left of $5$.
Step 3 :The solution to the inequality $4 x+6 \leq 3 x+11$ is $x \leq 5$. The graph of the solution is a number line with a closed circle at $5$ and shaded to the left. Therefore, the answer is \(\boxed{E. None of the above}\).