Question 6 of 26
Which statement proves that polygon \( A B C D \) is not a rectangle?
A. \( A B C D \) is a quadrilateral.
B. slope \( _{\overline{A D}} \cdot \) slope \( _{\bar{D}}=-1 \) and slope \( \overline{\overline{C C}} \cdot \) slope \( _{\overline{C D}}=-1 \)
C. The slope \( \overline{A B} \) and the slope of \( \overline{B C} \) are equal.
D. slope \( _{A D} \cdot \) slope \( _{A B} \neq-1 \) and slope \( \overline{B C} \cdot \) slope \( _{A B} \neq-1 \)
Solution
Step 1 :\text{A rectangle has right angles at all vertices}
Step 2 :\text{Right angles have slopes that are negative reciprocals}
Step 3 :\text{If two sides are equal, it does not guarantee the set of angles are right angles}