Step 1 :Given that the sample proportion (p̂) is 0.74, the population proportion (p) is 0.80, and the sample size (n) is 300.
Step 2 :We calculate the test statistic using the formula for the z-score, which is \((p̂ - p) / \sqrt{(p(1 - p) / n)}\).
Step 3 :Substituting the given values into the formula, we get a test statistic of approximately -2.60.
Step 4 :The p-value is the probability of observing a test statistic as extreme as the one calculated, assuming the null hypothesis is true. The null hypothesis in this case is that the proportion of workers employed from internet resume sites is 80%.
Step 5 :Using a standard normal distribution table, we calculate the p-value to be approximately 0.0094.
Step 6 :Final Answer: The test statistic is \(\boxed{-2.60}\) and the p-value is \(\boxed{0.0094}\).