Given a mean, standard deviation, and a raw score, find the corresponding z-score. Assume the distribution is normal. mean 100, standard deviation $5, x=108$

Step 1 ：Given a mean of 100, a standard deviation of 5, and a raw score of 108, we are to find the corresponding z-score. The z-score is a measure of how many standard deviations an element is from the mean.

Step 2 ：To find the z-score, we subtract the mean from the element and then divide by the standard deviation. In this case, we need to subtract the mean (100) from the raw score (108) and then divide by the standard deviation (5).

Step 3 ：Subtract the mean from the raw score: \(108 - 100 = 8\)

Step 4 ：Divide the result by the standard deviation: \(\frac{8}{5} = 1.6\)

Step 5 ：Final Answer: The z-score is \(\boxed{1.6}\)