Step 1 :Given the transformation T: \(x=4 u \cos (\pi v)\), \(y=4 u \sin (\pi v)\)
Step 2 :The Jacobian matrix of a vector-valued function is a matrix of all its first-order partial derivatives. In this case, we have a transformation T from (u, v) to (x, y). The Jacobian matrix J(u, v) is then a 2x2 matrix where the first row is the partial derivatives of x with respect to u and v, and the second row is the partial derivatives of y with respect to u and v.
Step 3 :The determinant of this matrix is the Jacobian determinant, which is what we're asked to compute.
Step 4 :The Jacobian determinant is given by the formula: \(J(u, v) = \frac{\partial x}{\partial u} * \frac{\partial y}{\partial v} - \frac{\partial x}{\partial v} * \frac{\partial y}{\partial u}\)
Step 5 :Compute these partial derivatives directly from the given transformation equations.
Step 6 :For \(x = 4u\cos(\pi v)\), we have \(\frac{\partial x}{\partial u} = 4\cos(\pi v)\) and \(\frac{\partial x}{\partial v} = -4\pi u\sin(\pi v)\)
Step 7 :For \(y = 4u\sin(\pi v)\), we have \(\frac{\partial y}{\partial u} = 4\sin(\pi v)\) and \(\frac{\partial y}{\partial v} = 4\pi u\cos(\pi v)\)
Step 8 :Substitute these into the formula for the Jacobian determinant to get \(J = 16\pi u\sin(\pi v)^2 + 16\pi u\cos(\pi v)^2\)
Step 9 :\(J(u, v) = 16\pi u\sin^2(\pi v) + 16\pi u\cos^2(\pi v)\) is the final answer.
Step 10 :\(\boxed{J(u, v) = 16\pi u\sin^2(\pi v) + 16\pi u\cos^2(\pi v)}\) does not match any of the given options A, B, C, or D. Therefore, the correct answer is not listed.