Step 1 :Translate the problem into a mathematical formula for sample size in a proportion: \(n = \frac{{Z^2 * p * (1-p)}}{{E^2}}\)
Step 2 :Identify the given values: Z-score (Z) for a 95% confidence level is 1.96, estimated proportion of the population (p) is 0.5, and the margin of error (E) is 6% or 0.06
Step 3 :Substitute the given values into the formula: \(n = \frac{{(1.96)^2 * 0.5 * (1-0.5)}}{{(0.06)^2}}\)
Step 4 :Simplify the equation to find the sample size (n)
Step 5 :Round the sample size (n) to the nearest whole number because you can't have a fraction of a person
Step 6 :Final Answer: The candidate would need to survey at least \(\boxed{267}\) people in the community in order to be within a 6% margin of error at a 95% confidence level