The label for atropine sulfate is shown. If the dose is for 0.2 milligrams of atropine sulfate, how many milliliters will be given? atropine sullate Injection, USP $10 \times 20, \mathrm{~mL}$ Multiple Dose Vials FOR SC, IM OR IV USE $400 \mathrm{mcg} / \mathrm{mL}$ $(0.4 \mathrm{mg} / \mathrm{mL})$ |P|Pharmaceuticals Each $\mathrm{mL}$ contains atropine sulfate $400 \mathrm{mcg}(0.4$ $\mathrm{mg}$ ), sodium chloride $9 \mathrm{mg}$ and benzyl alcohol 0.015 $\mathrm{mL}$ in Water for Injection. pH 3.0-6.5; Sulfuric acid added, if needed, for $\mathrm{pH}$ adjustment. POISON Usual Dose: See package insert. Store at controlled room temperature $15^{\circ}-30^{\circ} \mathrm{C}$ $\left(59^{\circ}-86^{\circ} \mathrm{F}\right)$. Cautlon: Federal law prohibits dispensing without prescription. Product Code $2210-43$ B-32210

Step 1 ：The question is asking for the volume of atropine sulfate solution needed to deliver a dose of 0.2 milligrams. From the label, we know that each milliliter of the solution contains 0.4 milligrams of atropine sulfate. Therefore, we need to calculate the volume that would contain 0.2 milligrams of atropine sulfate. This is a simple ratio problem, and we can solve it by setting up a proportion and solving for the unknown.

Step 2 ：Let's denote the required dose as \(dose_{required}\), which is 0.2 milligrams, and the concentration of the solution as \(concentration\), which is 0.4 milligrams per milliliter.

Step 3 ：We can set up the proportion as follows: \(\frac{dose_{required}}{concentration} = volume\)

Step 4 ：Solving for \(volume\), we get \(volume = \frac{dose_{required}}{concentration} = \frac{0.2}{0.4} = 0.5\) milliliters.

Step 5 ：Final Answer: The volume of atropine sulfate solution needed to deliver a dose of 0.2 milligrams is \(\boxed{0.5}\) milliliters.