Problem
Use the probability distribution to complete parts (a) through (d) below. The probability distribution of number of televisions per household in a small town \[ \begin{array}{lcc|c|c} \mathbf{x} & 0 & 1 & 2 & 3 \\ \mathrm{P}(\mathbf{x}) & 0.05 & 0.18 & 0.31 & 0.46 \end{array} \] (a) Find the probability of randomly selecting a household that has one or two televisions. The probability is 0.49 (Type an integer or a decimal. Eio not round.) (b) Find the probability of randomly selecting a household that has two or more televisions. The probability is (Type an integer or a decimal. Do not round.)
Solution
Step 1 ：The question asks for the probability of randomly selecting a household that has one or two televisions. This can be found by adding the probabilities of a household having one television and a household having two televisions.
Step 2 ：The probability of a household having one television is \(0.18\) and the probability of a household having two televisions is \(0.31\).
Step 3 ：Therefore, the probability of a household having one or two televisions is \(0.18 + 0.31 = 0.49\).
Step 4 ：Final Answer: The probability of randomly selecting a household that has one or two televisions is \(\boxed{0.49}\).
