Problem

$76 \%$ of U.S. adults think that political correctness is a problem in America today. You randomly select six U.S. adults and ask them whether they think that political correctness is a problem in America today. The random variable represents the number of U.S. adults who think that political correctness is a problem in America today. Answer the questions below. Find the variance of the binomial distribution. $\sigma^{2}=1.1$ (Round to the nearest tenth as needed.) Find the standard deviation of the binomial distribution. $\sigma=1.0$ (Round to the nearest tenth as needed.) Interpret the results in the context of the real-life situation. Most samples of 6 adults would differ from the mean by no more than (Type integers or decimals rounded to the nearest tenth as needed.)

Solution

Step 1 :The problem is asking for the variance and standard deviation of a binomial distribution. The variance of a binomial distribution is given by the formula \(\sigma^{2}=npq\), where n is the number of trials, p is the probability of success, and q is the probability of failure. The standard deviation is the square root of the variance. In this case, n=6 (the number of adults), p=0.76 (the percentage of adults who think political correctness is a problem), and q=1-p=0.24 (the percentage of adults who do not think political correctness is a problem).

Step 2 :Calculate the variance and standard deviation using the given values: n = 6, p = 0.76, q = 0.24. The variance is calculated as \(\sigma^{2}=npq = 6*0.76*0.24 = 1.0944\). The standard deviation is the square root of the variance, \(\sigma = \sqrt{1.0944} = 1.0461357464497616\).

Step 3 :The question asks for the results to be rounded to the nearest tenth. Therefore, round the variance and standard deviation to the nearest tenth: variance_rounded = 1.1, std_dev_rounded = 1.0.

Step 4 :Final Answer: The variance of the binomial distribution is \(\boxed{1.1}\) and the standard deviation of the binomial distribution is \(\boxed{1.0}\). This means that most samples of 6 adults would differ from the mean by no more than 1.0.

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Source: https://solvelyapp.com/problems/17708/

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