$76 \%$ of U.S. adults think that political correctness is a problem in America today. You randomly select six U.S. adults and ask them whether they think that political correctness is a problem in America today. The random variable represents the number of U.S. adults who think that political correctness is a problem in America today. Answer the questions below. Find the mean of the binomial distribution. $\mu=4.6$ (Round to the nearest tenth as needed.) Find the variance of the binomial distribution. $\sigma^{2}=1.1$ (Round to the nearest tenthas needed.) Find the standard deviation of the binomial distribution. $\sigma=$ (Round to the nearest tenth as needed.)

Step 1 ：The problem states that 76% of U.S. adults think that political correctness is a problem in America today. We are asked to find the mean, variance, and standard deviation of this binomial distribution when randomly selecting six U.S. adults.

Step 2 ：The mean of a binomial distribution is given by \(\mu = np\), where \(n\) is the number of trials and \(p\) is the probability of success. In this case, \(n = 6\) and \(p = 0.76\), so the mean is \(\mu = 6 \times 0.76 = 4.6\).

Step 3 ：The variance of a binomial distribution is given by \(\sigma^{2} = np(1-p)\). Substituting the given values, we get \(\sigma^{2} = 6 \times 0.76 \times (1 - 0.76) = 1.1\).

Step 4 ：The standard deviation of a binomial distribution is the square root of the variance. Therefore, the standard deviation is \(\sigma = \sqrt{1.1} = 1.0\) (rounded to the nearest tenth).

Step 5 ：Final Answer: The mean of the binomial distribution is \(\boxed{4.6}\), the variance is \(\boxed{1.1}\), and the standard deviation is \(\boxed{1.0}\).