$76 \%$ of U.S. adults think that political correctness is a problem in America today. You randomly select six U.S. adults and ask them whether they think that political correctness is a problem in America today. The random variable represents the number of U.S. adults who think that political correctness is a problem in America today. Answer the questions below. Find the mean of the binomial distribution. $\mu=4.6$ (Round to the nearest tenth as needed) Find the variance of the binomial distribution. $\sigma^{2}=\square$ (Round to the nearest terha as needed.)

Step 1 ：The problem is asking for the mean and variance of a binomial distribution. The mean and variance of a binomial distribution can be calculated using the formulas: Mean, \(\mu = np\) and Variance, \(\sigma^{2} = np(1-p)\) where n is the number of trials and p is the probability of success. In this case, n = 6 (the number of adults selected) and p = 0.76 (the percentage of adults who think political correctness is a problem).

Step 2 ：We have already been given the mean, \(\mu = 4.6\). Now we need to calculate the variance.

Step 3 ：Given n = 6 and p = 0.76, we can substitute these values into the formula for variance: \(\sigma^{2} = np(1-p)\).

Step 4 ：Substituting the given values, we get variance = 1.0944.

Step 5 ：Rounding to the nearest tenth, the variance of the binomial distribution is \(\boxed{1.1}\).