Step 1 :This problem is about a binomial distribution. The shape of the histogram for a binomial distribution depends on the probability of success (p). If p is close to 0.5, the distribution is approximately symmetric. If p is close to 0 or 1, the distribution is skewed. In this case, p = 0.76, so the distribution is skewed to the right.
Step 2 :For the second part of the question, we need to find the values of the random variable x that would be considered unusual. In a binomial distribution, values are considered unusual if their associated probabilities are less than or equal to 0.05.
Step 3 :Given that n = 5 and p = 0.76, we calculate the probabilities for each possible value of x (from 0 to 5). The probabilities are [0.0007962623999999999, 0.012607487999999998, 0.0798474239999999, 0.2528501759999998, 0.40034611199999987, 0.2535525376].
Step 4 :From these probabilities, we can see that the values of x that are associated with probabilities less than or equal to 0.05 are 0 and 1.
Step 5 :\(\boxed{\text{Final Answer: The shape of the histogram is skewed right. The values of the random variable x that would be considered unusual are 0 and 1.}}\)