Step 1 :The amplitude of a trigonometric function is the absolute value of the coefficient of the trigonometric part. In this case, the amplitude is \(6\).
Step 2 :The period of a trigonometric function is the length of one complete cycle. It is given by the formula \(2\pi / |B|\), where B is the coefficient of x in the argument of the trigonometric function. In this case, B is 4, so the period is \(2\pi / 4 = \pi / 2\).
Step 3 :The phase shift of a trigonometric function is the horizontal shift of the function. It is given by the formula \(-C / B\), where C is the constant in the argument of the trigonometric function. In this case, C is \(\pi / 2\), so the phase shift is \(-\pi / 2 / 4 = -\pi / 8\).
Step 4 :Final Answer: The amplitude is \(\boxed{6}\), the period is \(\boxed{\frac{\pi}{2}}\), and the phase shift is \(\boxed{-\frac{\pi}{8}}\).