Assume that a softball player has 0.56 probability of getting a hit in each at bat. Assume that the player bats four times. What is the probability that she gets a hit only in her first at bat?

Step 1 ：We are given a problem involving a softball player who has a 0.56 probability of getting a hit in each at bat. The player bats four times and we want to find the probability that she gets a hit only in her first at bat.

Step 2 ：This is a binomial distribution problem. The probability of getting a hit is 0.56 and the probability of not getting a hit is 1 - 0.56 = 0.44.

Step 3 ：We are looking for the probability that she gets a hit once and does not get a hit three times. The binomial probability formula is: \(P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k))\)

Step 4 ：In this case, n=4 (the number of times the player bats), k=1 (the number of times the player gets a hit), and p=0.56 (the probability of getting a hit).

Step 5 ：Substituting these values into the formula, we get: \(P(X=1) = C(4, 1) * (0.56^1) * ((1-0.56)^(4-1))\)

Step 6 ：Calculating the above expression, we get a probability of approximately 0.1908.

Step 7 ：Final Answer: The probability that the softball player gets a hit only in her first at bat is approximately \(\boxed{0.1908}\).