(1) \[ \begin{array}{l} y=3 x+2 \\ y=-5 x-1 \end{array} \]

Step 1 ：Given the two equations: \(y = 3x + 2\) and \(y = -5x - 1\)

Step 2 ：To find the point of intersection, we set the two equations equal to each other: \(3x + 2 = -5x - 1\)

Step 3 ：Rearrange the equation to isolate x: \(3x + 5x = -1 - 2\)

Step 4 ：Simplify the equation: \(8x = -3\)

Step 5 ：Divide both sides by 8 to solve for x: \(x = -3/8\)

Step 6 ：Substitute \(x = -3/8\) into the first equation to solve for y: \(y = 3(-3/8) + 2\)

Step 7 ：Simplify the equation to find y: \(y = -9/8 + 16/8 = 7/8\)

Step 8 ：Therefore, the point of intersection is \((-3/8, 7/8)\)

Step 9 ：Check the solution by substituting \((-3/8, 7/8)\) into the second equation: \(7/8 = -5(-3/8) - 1\)

Step 10 ：Simplify the equation: \(7/8 = 15/8 - 8/8\)

Step 11 ：The equation simplifies to \(7/8 = 7/8\), confirming that the solution is correct

Step 12 ：The final answer is \(\boxed{(-3/8, 7/8)}\)