Step 1 :This problem involves permutations because the order in which the numbers are entered is important. We are choosing 3 numbers from a set of 10, and each number can only be used once. This is a permutation problem, which can be represented as \(P(n, r)\), where \(n\) is the total number of items to choose from, and \(r\) is the number of items to choose. In this case, \(n=10\) and \(r=3\).
Step 2 :Calculate the number of permutations using the formula \(P(n, r) = \frac{n!}{(n-r)!}\).
Step 3 :Substitute \(n=10\) and \(r=3\) into the formula to get \(P(10, 3) = \frac{10!}{(10-3)!}\).
Step 4 :Simplify the expression to get the number of permutations as 720.
Step 5 :Final Answer: There are \(\boxed{720}\) ways to enter a three-digit code on a keypad with numbers 0-9, where each number may not be used more than once, and the order that you enter the numbers is important.