Step 1 :The problem involves a Poisson distribution, as it deals with the number of events (typographical errors) occurring within a fixed interval (a page). The mean number of errors per page is given as 8. We are asked to find the probability of exactly 5 errors, at most 5 errors, and more than 5 errors.
Step 2 :For the first part of the question, we need to find the probability of exactly 5 errors. The formula for the Poisson distribution is: \(P(X=k) = \frac{λ^k * e^-λ}{k!}\) where λ is the mean number of events, k is the actual number of events, and e is the base of the natural logarithm.
Step 3 :For the second part, we need to find the probability of at most 5 errors. This is the sum of the probabilities of 0, 1, 2, 3, 4, and 5 errors.
Step 4 :For the third part, we need to find the probability of more than 5 errors. This is 1 minus the probability of at most 5 errors.
Step 5 :An event is considered unusual if its probability is less than or equal to 0.05.
Step 6 :The probabilities of exactly five typographical errors, at most five typographical errors, and more than five typographical errors are approximately 0.0916, 0.1912, and 0.8088, respectively.
Step 7 :None of the events are unusual. Therefore, the answer is \(\boxed{D}\).