Step 1 :We are given that the probability of making a sale on any given call is 0.14. The events are independent, meaning each call does not affect the outcome of the others. This is a geometric distribution problem.
Step 2 :For part (a), we need to find the probability that the first success (sale) occurs on the fifth call. This means that the first four calls are failures (no sale) and the fifth call is a success. The probability for this event is approximately 0.077.
Step 3 :For part (b), we need to find the probability that the first success occurs on the first, second, or third call. This means we need to find the sum of the probabilities of a success on the first call, a success on the second call (after one failure), and a success on the third call (after two failures). The probability for this event is approximately 0.364.
Step 4 :For part (c), we need to find the probability that the first three calls are all failures (no sale). The probability for this event is approximately 0.636.
Step 5 :An event is considered unusual if its probability is less than or equal to 0.05. Comparing the probabilities of the events to this threshold, we can see that none of the events are unusual.
Step 6 :Final Answer: \(\boxed{\text{D. None of the events are unusual}}\)