Graph $h(x)=0.5(x+2)^{2}-4$ by following these steps: Step 1: Identify $a, h$, and $k$. \[ a= \] \begin{tabular}{|l|l|} \hline$x$ & $y$ \\ \hline & \\ & \\ \hline \end{tabular} Check

Step 1 ：Identify the values of a, h, and k in the given function $h(x)=0.5(x+2)^{2}-4$. The function is in the form of a quadratic function $f(x) = a(x-h)^2 + k$, where a is the coefficient of the square term, h is the value that shifts the graph horizontally, and k is the value that shifts the graph vertically.

Step 2 ：In the given function, we can see that $a=0.5$, $h=-2$ (since the function is $(x+2)$, the shift is opposite in sign, so $h=-2$), and $k=-4$.

Step 3 ：The final values of $a$, $h$, and $k$ are $a=0.5$, $h=-2$, and $k=-4$.