Step 1 :Given the equation \(\sqrt{x^{2}+2 x y+y^{6}}=8\), we are asked to evaluate \(\frac{d y}{d x}\). We assume that the equation implicitly defines \(y\) as a differentiable function of \(x\).
Step 2 :We define a function \(F(x, y)=\sqrt{x^{2}+2 x y+y^{6}}-8=0\).
Step 3 :We find the partial derivatives of \(F\) with respect to \(x\) and \(y\), denoted as \(F_{x}\) and \(F_{y}\) respectively.
Step 4 :\(F_{x} = \frac{x + y}{\sqrt{x^{2} + 2*x*y + y^{6}}}\)
Step 5 :\(F_{y} = \frac{x + 3*y^{5}}{\sqrt{x^{2} + 2*x*y + y^{6}}}\)
Step 6 :We can find \(\frac{d y}{d x}\) using the implicit differentiation method, which gives us \(\frac{d y}{d x} = -\frac{F_{x}}{F_{y}}\).
Step 7 :Substituting the values of \(F_{x}\) and \(F_{y}\) into the equation, we get \(\frac{d y}{d x} = -\frac{x + y}{x + 3y^{5}}\).
Step 8 :\(\boxed{\frac{d y}{d x} = -\frac{x + y}{x + 3y^{5}}}\) is the final answer.