Step 1 :First, we calculate the partial derivatives of \(w\) with respect to \(x\) and \(y\).
Step 2 :\[\frac{\partial w}{\partial x} = 8\cos 8x \cos 2y\]
Step 3 :\[\frac{\partial w}{\partial y} = -2\sin 8x \sin 2y\]
Step 4 :Next, we calculate the derivatives of \(x\) and \(y\) with respect to \(t\).
Step 5 :\[\frac{dx}{dt} = \frac{1}{4}\]
Step 6 :\[\frac{dy}{dt} = 5t^{4}\]
Step 7 :Finally, we use the Chain Rule to find \(\frac{dw}{dt}\).
Step 8 :\[\frac{dw}{dt} = \frac{\partial w}{\partial x} \cdot \frac{dx}{dt} + \frac{\partial w}{\partial y} \cdot \frac{dy}{dt}\]
Step 9 :Substitute the above values into the equation.
Step 10 :\[\frac{dw}{dt} = 8\cos 8x \cos 2y \cdot \frac{1}{4} - 2\sin 8x \sin 2y \cdot 5t^{4}\]
Step 11 :\[\frac{dw}{dt} = 2\cos 8x \cos 2y - 10t^{4}\sin 8x \sin 2y\]
Step 12 :Substitute \(x = \frac{t}{4}\) and \(y = t^{5}\) into the equation.
Step 13 :\[\frac{dw}{dt} = 2\cos 2t \cos 2t^{5} - 10t^{4}\sin 2t \sin 2t^{5}\]
Step 14 :\[\frac{dw}{dt} = \boxed{2\cos 2t \cos 2t^{5} - 20t^{4}\sin 2t \sin 2t^{5}}\]