Solve. \[ \frac{7 y}{y-8}-\frac{56}{y+8}=\frac{896}{y^{2}-64} \]

Step 1 ：Given the equation \(\frac{7 y}{y-8}-\frac{56}{y+8}=\frac{896}{y^{2}-64}\)

Step 2 ：First, we need to clear the fractions. To do this, we multiply each term by the least common denominator (LCD) of all the fractions. The LCD in this case is \(y^{2}-64\), which is the product of \(y-8\) and \(y+8\).

Step 3 ：After multiplying each term by the LCD, we get a quadratic equation which we can solve for \(y\).

Step 4 ：Solving the quadratic equation, we get two solutions: \(y = -8\) and \(y = 8\).

Step 5 ：However, we need to check these solutions in the original equation because in rational equations, some solutions might be extraneous (not valid).

Step 6 ：Both solutions are not valid because they make the denominator of the original equation zero.

Step 7 ：\(\boxed{\text{Therefore, the original equation has no solution.}}\)