Step 1 :Given the distance $d=190$ metres to 2 significant figures and time $t=8.1$ seconds to 2 significant figures.
Step 2 :The formula connecting speed $(s)$, distance $(d)$ and time $(t)$ is $s=\frac{d}{t}$.
Step 3 :To find the lower and upper bounds of speed, we need to consider the lower and upper bounds of distance and time.
Step 4 :For distance, the lower bound is 185 and the upper bound is 195 (to 2 significant figures). For time, the lower bound is 8.05 and the upper bound is 8.15 (to 2 significant figures).
Step 5 :The lower bound of speed is found by dividing the upper bound of distance by the lower bound of time. So, $s_{lower} = \frac{d_{upper}}{t_{lower}} = \frac{195}{8.05} = 24.224$ m/s.
Step 6 :The upper bound of speed is found by dividing the lower bound of distance by the upper bound of time. So, $s_{upper} = \frac{d_{lower}}{t_{upper}} = \frac{185}{8.15} = 22.699$ m/s.
Step 7 :Final Answer: The lower bound of speed is \(\boxed{22.699}\) m/s and the upper bound of speed is \(\boxed{24.224}\) m/s.