1) Sein foter o grafico e obrervando apenas 0 coehtiente a verifque se a pardbola que $f$ de cada una das seguntes funcoes tem a concavidade voltada para cima ou para baixo. a) $y=2 x^{2}-2 x+1$ b) $y=-x^{2}+4 x-4$ c) $y=-3 x^{2}+x-4$ d) $y=x^{2}+5 x$ e) $y=x^{2}$ a) Determine os zeros ( se existentes) das funçes quadraticas e faça um esboco do graf (1,0) a) $y=x^{2}-6 x+8$ b) $y=x^{2}+2$ 3) O conjunto soluctैo da equacto $x^{2}-64=0$ e: $(1,0)$ a) $+8=8$ b) $+4,4$ c) 0,1 4) Equardes do segundo grau sto do tipo $a x^{2}+b x+c=a$ com base nisso, na equaç̧० valores de "a" "b" $e^{4 e^{*}}$ saco, respectivamente $\{1,0\}$ a) $3 / 2 / 0$ b) $3 / 2 / 0$ () $3 / 2 / 1$

Step 1 ：a) \(y = 2x^2 - 2x + 1\) has a positive leading coefficient, so the parabola opens upwards.

Step 2 ：b) \(y = -x^2 + 4x - 4\) has a negative leading coefficient, so the parabola opens downwards.

Step 3 ：c) \(y = -3x^2 + x - 4\) has a negative leading coefficient, so the parabola opens downwards.

Step 4 ：d) \(y = x^2 + 5x\) has a positive leading coefficient, so the parabola opens upwards.

Step 5 ：e) \(y = x^2\) has a positive leading coefficient, so the parabola opens upwards.

Step 6 ：a) To find the zeros of \(y = x^2 - 6x + 8\), set \(y = 0\) and solve for \(x\): \(x^2 - 6x + 8 = 0\). Factoring, we get \((x - 2)(x - 4) = 0\), so the zeros are \(x = 2\) and \(x = 4\).

Step 7 ：b) To find the zeros of \(y = x^2 + 2\), set \(y = 0\) and solve for \(x\): \(x^2 + 2 = 0\). This equation has no real solutions, so there are no zeros.

Step 8 ：The solution set of the equation \(x^2 - 64 = 0\) is \(x = \pm 8\), or \(\{ -8, 8 \}\).

Step 9 ：For the quadratic equation \(ax^2 + bx + c = a\), the coefficients are \(a = 3\), \(b = 2\), and \(c = 0\).