Problem
8) $\frac{3}{x-2}+\frac{4 x}{x+1}$
Solution
Step 1 ：Find a common denominator: \(\frac{3(x+1)}{(x-2)(x+1)} + \frac{4x(x-2)}{(x+1)(x-2)}\)
Step 2 ：Combine the fractions: \(\boxed{\frac{4x^2 - 5x + 3}{x^2 - x - 2}}\)
Step 1 ：Find a common denominator: \(\frac{3(x+1)}{(x-2)(x+1)} + \frac{4x(x-2)}{(x+1)(x-2)}\)
Step 2 ：Combine the fractions: \(\boxed{\frac{4x^2 - 5x + 3}{x^2 - x - 2}}\)
