Problem

\( -9<6+3 x \leqslant 12 \)

Solution

Step 1 :\( -9 < 6 + 3x \leqslant 12 \)

Step 2 :\( -9 - 6 < 3x \leqslant 12 - 6 \)

Step 3 :\( -15 < 3x \leqslant 6 \)

Step 4 :\( \frac{-15}{3} < x \leqslant \frac{6}{3} \)

Step 5 :\( -5 < x \leqslant 2 \)

From Solvely APP
Source: https://solvelyapp.com/problems/16953/

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