Problem
\[ \frac{(2 x-3)}{5}+\frac{(4 x-1)}{10}=1 \] Salve for \( x \)
Solution
Step 1 ：\[ 2( \frac{(2x-3)}{5}+\frac{(4x-1)}{10} ) = 2(1) \]
Step 2 ：\[ \frac{(4x-6)}{5}+\frac{(4x-1)}{5}=2 \]
Step 3 ：\[ \frac{(8x-7)}{5}=2 \]
Step 4 ：\[ x=\frac{17}{8} \]
