\begin{tabular}{|c|c|} \hline Time (x axis) (seconds) & Position (y axis) (meters) \\ \hline 0 & 0 \\ \hline 5 & 20 \\ \hline 10 & 40 \\ \hline 15 & 50 \\ \hline 20 & 55 \\ \hline 30 & 60 \\ \hline 35 & 70 \\ \hline 40 & 70 \\ \hline 45 & 70 \\ \hline 50 & 55 \\ \hline \end{tabular} Insert your graph here for Distance vs Time of a Moving Object. Questions for Activity 1 Question 1: What is the average speed of the train during the time interval from 0 s to $10 \mathrm{~s}$ ? Question 2: Using the equation: $v=\frac{s 2-s 1}{t 2-t 1}$, calculate the average speed of the train as it moves from position $\mathrm{x}=50 \mathrm{~m}$ to $\mathrm{x}=60 \mathrm{~m}$. Question 3: What does the slope of the line during each time interval represent?
Solution
Step 1 ：The problem is asking for the average speed of the train during the time interval from 0s to 10s.
Step 2 ：To calculate this, we need to use the formula for average speed, which is total distance travelled divided by total time taken.
Step 3 ：From the table, we can see that the distance travelled from 0s to 10s is 40 meters.
Step 4 ：The time taken is 10 seconds.
Step 5 ：So, we can calculate the average speed by dividing 40 meters by 10 seconds.
Step 6 ：\(\text{distance_travelled} = 40\)
Step 7 ：\(\text{time_taken} = 10\)
Step 8 ：\(\text{average_speed} = \frac{\text{distance_travelled}}{\text{time_taken}} = \frac{40}{10} = 4.0\)
Step 9 ：Final Answer: The average speed of the train during the time interval from 0s to 10s is \(\boxed{4.0}\) meters per second.
