Step 1 :\(I_x = \frac{1}{12}bh^3\)
Step 2 :\(S_x = \frac{1}{6}bh^2\)
Step 3 :\begin{array}{|c|c|c|} \hline \text{Section} & I_x & S_x \\ \hline a & 2 \times (\frac{1}{12})(2)(8^3) = 853.3333 & 2 \times (\frac{1}{6})(2)(8^2) = 170.6667 \\ \hline b & 4 \times (\frac{1}{12})(4)(8^3) = 6826.6667 & 4 \times (\frac{1}{6})(4)(8^2) = 682.6667 \\ \hline c & 2 \times (\frac{1}{12})(2)(10^3) = 1666.6667 & 2 \times (\frac{1}{6})(2)(10^2) = 666.6667 \\ \hline d & 6 \times (\frac{1}{12})(6)(6^3) = 6480 & 6 \times (\frac{1}{6})(6)(6^2) = 432 \\ \hline e & 2 \times (\frac{1}{12})(2)(12^3) = 2880 & 2 \times (\frac{1}{6})(2)(12^2) = 576 \\ \hline \end{array}\)
Step 4 :\text{The most economical section is } a