If $f(x)=8^{x^{2}-6}-2$, what is the value of $f(-2)$, to the nearest hundredth (if necessary)?

Step 1 ：The problem is asking for the value of the function \(f(x) = 8^{x^{2}-6}-2\) when \(x=-2\).

Step 2 ：To find this, we substitute \(x=-2\) into the function.

Step 3 ：So, \(f(-2) = 8^{(-2)^{2}-6}-2\).

Step 4 ：Solving this, we get \(f(-2) = -1.984375\).

Step 5 ：Rounding to the nearest hundredth, we get \(-1.98\).

Step 6 ：Final Answer: The value of \(f(-2)\), to the nearest hundredth, is \(\boxed{-1.98}\).