Step 1 :Given the function \(N(t)=\frac{30,000}{1+40 e^{-2.5 t}}\), which describes the number of people, \(N(t)\), who become ill with a virus \(t\) weeks after its initial outbreak in a town with 30,000 inhabitants.
Step 2 :For part a, we need to substitute \(t=0\) into the function to find the number of people who were ill when the epidemic began. This gives us \(N(0)=\frac{30,000}{1+40 e^{-2.5 \times 0}}\), which simplifies to approximately 732 people.
Step 3 :For part b, we need to substitute \(t=4\) into the function to find the number of people who were ill by the end of the fourth week. This gives us \(N(4)=\frac{30,000}{1+40 e^{-2.5 \times 4}}\), which simplifies to approximately 29946 people.
Step 4 :For part c, the question is asking why the spread of an epidemic can't grow indefinitely. This is a theoretical question and doesn't require any calculations. The answer is that the number of ill people cannot exceed the population of the town. This is because the function \(N(t)\) has a horizontal asymptote at \(N=30000\), which represents the total population of the town. The number of ill people can't exceed this number.
Step 5 :Final Answer: a. When the epidemic began, approximately \(\boxed{732}\) people were ill with the virus. b. By the end of the fourth week, approximately \(\boxed{29946}\) people were ill with the virus. c. The spread of an epidemic can't grow indefinitely because \(\boxed{\text{The number of ill people cannot exceed the population of the town.}}\)