Based on a poll, among adults who regret getting tattoos, $16 \%$ say that they were too young when they got their tattoos. Assume that nine adults who regret getting tattoos are randoml and find the indicated probability. Complete parts (a) through (d) below. a. Find the probability that none of the selected adults say that they were too young to get tattoos. 0.2082 (Round to four decimal places as needed.) b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos. (Round to four decimal places as needed.)

Step 1 ：This problem is about the binomial distribution. The binomial distribution model is appropriate for a quantitative response that arises from a series of 'n' trials, each of which can result in a 'success' with probability 'p' and a 'failure' with probability '1-p'. In this case, 'n' is the number of adults who regret getting tattoos, and 'p' is the probability that an adult says that they were too young when they got their tattoos.

Step 2 ：Let's denote 'n' as the number of adults who regret getting tattoos, 'p' as the probability that an adult says that they were too young when they got their tattoos, and 'k' as the number of successes we are interested in.

Step 3 ：For this problem, we have n=9, p=0.16.

Step 4 ：Part a asks for the probability that none of the selected adults say that they were too young to get tattoos. This is calculated as \((1-p)^n\). Substituting the given values, we get a probability of \(0.2082\).

Step 5 ：Part b asks for the probability that exactly one of the selected adults says that he or she was too young to get tattoos. This is calculated as \(nCk * (p^k) * ((1-p)^(n-k))\). Here, k=1. Substituting the given values, we get a probability of \(0.3569\).

Step 6 ：Final Answer: The probability that none of the selected adults say that they were too young to get tattoos is \(\boxed{0.2082}\). The probability that exactly one of the selected adults says that he or she was too young to get tattoos is \(\boxed{0.3569}\).