The general term of a sequence is given. Determine whether the sequence is arithmetic, geometric, or neither. If the sequence is arithmetic, find the common difference; if it is geometric, find the common ratio. \[ a_{n}=n-16 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The sequence is arithmetic with a common difference of B. The sequence is geometric with a common ratio of c. The sequence is neither arithmetic nor geometric.

Step 1 ：The given sequence is \(a_{n}=n-16\). This is a linear function of \(n\), which suggests that the sequence is arithmetic.

Step 2 ：In an arithmetic sequence, each term is obtained by adding a constant difference to the previous term.

Step 3 ：The difference between consecutive terms can be found by subtracting \(a_{n}\) from \(a_{n+1}\), which gives \(a_{n+1} - a_{n} = (n+1-16) - (n-16) = 1\).

Step 4 ：Therefore, the common difference is 1.

Step 5 ：Final Answer: The sequence is arithmetic with a common difference of \(\boxed{1}\).