Use the formula for the general term (the $\mathrm{nth}$ term) of a geometric sequence to find the indicated term of the following sequence with the given first term, $a_{1}$, and common ratio, $r$. Find $a_{10}$ when $a_{1}=6$ and $r=3$. $a_{10}=\square$ (Type an integer or a decimal.)

Step 1 ：Given the first term of the geometric sequence, \(a_{1} = 6\), the common ratio, \(r = 3\), and we need to find the 10th term, \(a_{10}\).

Step 2 ：The formula for the nth term of a geometric sequence is given by \(a_{n} = a_{1} * r^{(n-1)}\).

Step 3 ：Substitute the given values into the formula: \(a_{10} = 6 * 3^{(10-1)}\).

Step 4 ：Simplify the expression to find the value of \(a_{10}\).

Step 5 ：Final Answer: \(a_{10}=\boxed{118098}\).