Suppose you walk $18.0 \mathrm{~m}$ straight west and then $25.0 \mathrm{~m}$ straight north. (If you represent the two legs of the walk as vector displacements $\mathbf{A}$ and $\mathbf{B}$, as in the figure below, then this problem asks you to find their sum $\mathbf{R}=\mathbf{A}+\mathbf{B}$.) (1) How far, in meters, are you from your starting point? (Enter a number.) $\mathrm{m}$ What is the compass direction of a line connecting your starting point to your final position measured in degrees west of north? (Enter a number.)

Step 1 ：Suppose you walk 18.0 m straight west and then 25.0 m straight north. If you represent the two legs of the walk as vector displacements A and B, then this problem asks you to find their sum R=A+B.

Step 2 ：This problem can be solved using the Pythagorean theorem. The distance from the starting point to the final position is the hypotenuse of a right triangle with sides of 18.0 m and 25.0 m.

Step 3 ：The Pythagorean theorem states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. Therefore, we can calculate the distance as follows: \[\sqrt{(18.0 \mathrm{~m})^2 + (25.0 \mathrm{~m})^2}\]

Step 4 ：Final Answer: The distance from the starting point to the final position is approximately \(\boxed{30.81 \mathrm{~m}}\).