Step 1 :The given equation is a quadratic equation. To solve it, we need to rewrite it in the standard form of a quadratic equation, which is \(ax^2 + bx + c = 0\).
Step 2 :Rewrite the given equation \(x^{2}=6 x+27\) in the standard form: \(x^2 - 6x - 27 = 0\).
Step 3 :Factor the quadratic equation to find the roots.
Step 4 :The solutions to the equation are \(x = -3\) and \(x = 9\). These are the values of x that make the equation true.
Step 5 :Final Answer: The solution set is \(\boxed{-3, 9}\).