Step 1 :Given matrices $A=\left[\begin{array}{rr}7 & -3 \ -4 & -7 \ 7 & -9\end{array}\right]$ and $B=\left[\begin{array}{rr}0 & 9 \ -2 & -5 \ -7 & 6\end{array}\right]$
Step 2 :For matrix addition and subtraction, we perform the operations element-wise. That is, the element in the i-th row and j-th column of the resulting matrix is the sum or difference of the elements in the i-th row and j-th column of the original matrices.
Step 3 :For scalar multiplication, we multiply each element of the matrix by the scalar.
Step 4 :Performing these operations, we find:
Step 5 :$A+B=\left[\begin{array}{rr}7 & 6 \ -6 & -12 \ 0 & -3\end{array}\right]$
Step 6 :$A-B=\left[\begin{array}{rr}7 & -12 \ -2 & -2 \ 14 & -15\end{array}\right]$
Step 7 :$2A=\left[\begin{array}{rr}14 & -6 \ -8 & -14 \ 14 & -18\end{array}\right]$
Step 8 :For the operation $5A-3B$, we first multiply each matrix by its respective scalar, then subtract the two resulting matrices element-wise.
Step 9 :Performing this operation, we find $5A-3B=\left[\begin{array}{rr}35 & -42 \ -14 & -20 \ 56 & -63\end{array}\right]$
Step 10 :Thus, the final answers are \(\boxed{A+B=\left[\begin{array}{rr}7 & 6 \ -6 & -12 \ 0 & -3\end{array}\right]}\), \(\boxed{A-B=\left[\begin{array}{rr}7 & -12 \ -2 & -2 \ 14 & -15\end{array}\right]}\), \(\boxed{2A=\left[\begin{array}{rr}14 & -6 \ -8 & -14 \ 14 & -18\end{array}\right]}\), and \(\boxed{5A-3B=\left[\begin{array}{rr}35 & -42 \ -14 & -20 \ 56 & -63\end{array}\right]}\)