Mrs. Obama implemented a program to get "children playing outside" and predicts it increased the proportion of time children spent outside on the weekends to more than $15 \%$. To test this prediction, she surveyed 300 random family participants and found that children of 205 families spent more than $15 \%$ of their weekend time outside. The following is the setup for this hypothesis test: \[ \begin{array}{l} H_{0}: p=0.15 \\ H_{a}: p>0.15 \end{array} \] The $p$-value for this hypothesis test is 0.002 . At the $2.5 \%$ significance level, should she reject or fail to reject the null hypothesis?

Step 1 ：Mrs. Obama implemented a program to get 'children playing outside' and predicts it increased the proportion of time children spent outside on the weekends to more than 15%. To test this prediction, she surveyed 300 random family participants and found that children of 205 families spent more than 15% of their weekend time outside.

Step 2 ：The following is the setup for this hypothesis test: \[\begin{array}{l} H_{0}: p=0.15 \\ H_{a}: p>0.15 \end{array}\]

Step 3 ：The p-value for this hypothesis test is 0.002.

Step 4 ：At the 2.5% significance level, we need to decide whether to reject or fail to reject the null hypothesis.

Step 5 ：The p-value is the probability of obtaining the observed data (or data more extreme) if the null hypothesis is true. If the p-value is less than the significance level, we reject the null hypothesis.

Step 6 ：In this case, the p-value is 0.002, which is less than the significance level of 0.025.

Step 7 ：Final Answer: Since the p-value is less than the significance level, we should \(\boxed{\text{Reject the null hypothesis}}\).