Step 1 :Let's denote the number of gyro combos prepared and sold each week as $x$. The weekly cost function, $C(x)$, for the food truck vendor is the sum of fixed and variable costs, which is $560 + 5.30x$.
Step 2 :The revenue function, $R(x)$, is given as $-0.001x^2 + 8.54x$. The profit function, $P(x)$, is the difference between the revenue and the cost functions, which is $R(x) - C(x) = -0.001x^2 + 8.54x - (560 + 5.30x) = -0.001x^2 + 3.24x - 560$.
Step 3 :To find the number of gyro combos that should be prepared and sold each week to maximize profit, we need to find the maximum of the profit function. The profit function is a quadratic function, and its maximum occurs at the vertex. The x-coordinate of the vertex of a quadratic function $ax^2 + bx + c$ is given by $-b/2a$. So, the number of gyro combos that should be prepared and sold each week to maximize profit is $x = -3.24/(2*(-0.001))$.
Step 4 :Substitute $x$ into the profit function $P(x)$ to get the maximum weekly profit. The maximum weekly profit is $P(x) = -0.001*(-3.24/(2*(-0.001)))^2 + 3.24*(-3.24/(2*(-0.001))) - 560$.
Step 5 :Finally, we need to round the results to two decimal places as needed.