Problem
PAPER 2 - ANSWER ALL OUESTIONS IN THIS SECTION 1.a) If $\frac{d}{t-p}=\frac{t}{d+p}$ i) make " $p$ " the subject of the relation. ii) find the value of " $p$ " if $t=13$ and $d=6$ ) Find the truth set of \[ 3(x-1) \leq 1 / 2(x+1)-6 \] 2.a) Draw a multiplication cable for arithmetic modulo on the set $P=\{1,4,9,11\}$. Use your table to find truth set of
Solution
Step 1 ：Given the equation \(\frac{d}{t-p}=\frac{t}{d+p}\), we are asked to make 'p' the subject of the relation.
Step 2 ：By cross multiplying and simplifying, we get the equation in the form 'p = t - d'.
Step 3 ：Now, we substitute the given values of 't' and 'd' into the equation to find the value of 'p'.
Step 4 ：Substituting 't' = 13 and 'd' = 6, we get 'p' = 13 - 6.
Step 5 ：Calculating the above expression, we find that 'p' = 7.
Step 6 ：Final Answer: The value of 'p' when 't' is 13 and 'd' is 6 is \(\boxed{7}\).
