se the information listed below to solve parts a through $\mathbf{h}$. Suppose that the demand and price for a certain model of a youth wristwatch are related by the following equation \[ p=D(q)=28-2.25 q \] where $p$ is the price (in dollars) and $q$ is the quantity demanded (in hundreds). Find the price at each level of demand. Answer parts a through d. a. Find the price when the demand is 0 watches. The price when the demand is 0 watches is $\$ 28$. b. Find the price when the demand is 400 watches. The price when the demand is 400 watches is $\$ 19$. c. Find the quantity demanded for the watch when the price is $\$ 10$. At a price of $\$ 10$, the demand is for watches.

Step 1 ：The demand and price for a certain model of a youth wristwatch are related by the equation \(p=D(q)=28-2.25 q\), where \(p\) is the price (in dollars) and \(q\) is the quantity demanded (in hundreds).

Step 2 ：To find the price when the demand is 0 watches, we substitute \(q=0\) into the equation. This gives us \(p=D(0)=28-2.25*0=28\). So, the price when the demand is 0 watches is \$28.

Step 3 ：To find the price when the demand is 400 watches, we substitute \(q=4\) into the equation (since \(q\) is in hundreds). This gives us \(p=D(4)=28-2.25*4=19\). So, the price when the demand is 400 watches is \$19.

Step 4 ：To find the quantity demanded for the watch when the price is \$10, we rearrange the equation to solve for \(q\) when \(p=10\). This gives us \(q=(28-10)/2.25=8\). Since \(q\) is in hundreds, the quantity demanded for the watch when the price is \$10 is \(8*100=800\) watches.

Step 5 ：Final Answer: The quantity demanded for the watch when the price is \$10 is \(\boxed{800}\) watches.