Problem
\[
f(x)=\left\{\begin{array}{ll}
x^{2} & x \leq-2 \\
2 x & -2
Solution
Step 1 ：Since 0 is greater than -2 and less than 2, it falls under the second condition. Therefore, we need to apply the function \(2x\) to 0.
Step 2 ：Substitute \(x = 0\) into the function \(2x\).
Step 3 ：Calculate the value of the function, which is \(2 * 0 = 0\).
Step 4 ：Final Answer: \(f(0) = \boxed{0}\)
From Solvely APP
Solution
Step 1 ：Since 0 is greater than -2 and less than 2, it falls under the second condition. Therefore, we need to apply the function \(2x\) to 0.
Step 2 ：Substitute \(x = 0\) into the function \(2x\).
Step 3 ：Calculate the value of the function, which is \(2 * 0 = 0\).
Step 4 ：Final Answer: \(f(0) = \boxed{0}\)
