Step 1 :Given the equation \(9 x^{\frac{2}{3}}-44 x^{\frac{1}{3}}-5=0\)
Step 2 :Make an appropriate substitution and rewrite the equation in quadratic form. Let \(u=x^{\frac{1}{3}}\), then the quadratic equation in \(u\) is \(9u^2 - 44u - 5 = 0\)
Step 3 :Solve the quadratic equation for \(u\). The solutions are \(u = -\frac{1}{9}\) and \(u = 5\)
Step 4 :Substitute back to find the value of \(x\). The solutions for \(x\) are \(x = (-\frac{1}{9})^3 = -\frac{1}{729}\) and \(x = 5^3 = 125\)
Step 5 :Final Answer: The solution set is \(\boxed{\{-\frac{1}{729}, 125\}}\)