Step 1 :Let R be the revenue and n be the number of chairs ordered. We can write a function to calculate the revenue based on the number of chairs:
Step 2 :\[ R(n) = \begin{cases} 100n & \text{if } n \leq 300 \\ 100n - 0.25(n-300)^2 & \text{if } n > 300 \end{cases} \]
Step 3 :To find the largest revenue, we need to find the maximum value of R(n) for n > 300. We can do this by taking the derivative of R(n) with respect to n and setting it to 0:
Step 4 :\[ \frac{dR}{dn} = 100 - 0.5(n-300) \]
Step 5 :\[ 0 = 100 - 0.5(n-300) \]
Step 6 :\[ n = 400 \]
Step 7 :Since the maximum value occurs at n = 400, we can plug this value back into the revenue function to find the largest revenue:
Step 8 :\[ R(400) = 100(400) - 0.25(400-300)^2 \]
Step 9 :\[ R(400) = \boxed{30,625} \]
Step 10 :To find the smallest revenue, we need to consider the case when the customer orders the minimum number of chairs, which is 1:
Step 11 :\[ R(1) = 100(1) \]
Step 12 :\[ R(1) = \boxed{100} \]
Step 13 :The largest revenue the company can make under this deal is $30,625, and the smallest revenue is $100.